Linear function questions demand a deep understanding of real-world scenarios, variable definition and complex function setups, but we will show you a fool-proof way to tackle these problems.
Algebra problems comprise ~35% of the questions on the SAT math section, and one of the most common types of algebra questions is linear equations in one variable. At their core, these equations are simple enough, structured around the basic principle of finding the value of a single variable, usually denoted as x.
However, the simplicity is deceptive. These equations can easily become complex, involving fractions and parentheses and requiring numerous steps to solve. The difficulty escalates when equations are compounded with extraneous terms or require manipulations that are not immediately apparent.
Solving single-variable linear equation problems is not just about finding the right answer; it is about understanding the logical process that leads to that answer. By following our 4-step process below, you will learn to systematically solve these problems every time, no matter how complex they seem.
The first step is to streamline the equation by reducing complexity through algebraic manipulations, such as combining similar terms and resolving parentheses, which is crucial for making the equation more manageable and clearer to solve.
Add or subtract terms with the same variable to simplify the equation.
Use the distributive property to multiply terms outside the parentheses with those inside.
By finding a common denominator and multiplying all terms by it, you can eliminate fractions.
Organize the equation for clarity, often by moving all terms with the variable to one side and constants to the other.
Address unique situations like products equalling zero or variables in denominators, which require specific approaches.
Let us take an equation and apply the simplification steps:
3(x + 2) - 2x = 5 + x - 1
First, eliminate the parentheses and combine like terms: 3x + 6 - 2x = 5 + x - 1
Then simplify further: 3x - 2x - x = 5 - 1 - 6
The equation becomes: -x = -2, so x = 2
This step involves manipulating the equation to isolate the variable on one side, which is key to solving the equation and finding the value of the variable.
Use addition, subtraction, multiplication, or division to get the variable by itself.
If there is a number added or subtracted from the variable, do the opposite operation on both sides.
If the variable is multiplied or divided by a number, reverse the operation on both sides.
3x + 7 = 10. First, undo addition: 3x = 10 - 7 = 3. Then divide by 3: x = 1.
After isolating the variable, this step involves further simplification to ensure the equation is in its simplest form.
Check if the equation can be simplified further by combining like terms or performing basic arithmetic.
If your solution is a fraction, reduce it to its simplest form.
Convert decimals to fractions or percentages if it makes the equation simpler.
4x + 2x - x = 12. Combine: 5x = 12. Simplify: x = 12/5.
This crucial step ensures that the solution you have found actually satisfies the original equation, verifying the accuracy of your work.
Replace the variable with your solution in the original equation to see if the equation holds true.
For 3x + 4 = 13 where x = 3: substitute 3(3) + 4 = 13. Check: 9 + 4 = 13. The solution is correct.